Given a string s
containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
An input string is valid if:
- Open brackets must be closed by the same type of brackets.
- Open brackets must be closed in the correct order.
- Every close bracket has a corresponding open bracket of the same type.
Example 1:Input: s = “()” Output: true
Example 2:Input: s = “()[]{}” Output: true
Example 3:Input: s = “(]” Output: false
Constraints:
1 <= s.length <= 104
s
consists of parentheses only'()[]{}'
.
The problem is simple, just find if the coming parenthese matches with the lastest element in the stack.
class Solution:
def isValid(self, s: str) -> bool:
match_dict = {
")": "(",
"]": "[",
"}": "{"
}
stack = []
for parenthese in s:
if not stack:
stack.append(parenthese)
elif stack[-1] == match_dict.get(parenthese):
stack.pop()
else:
stack.append(parenthese)
return len(stack) == 0
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